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Latihan Limit Fungsi (1)
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Soal berikut merupakan soal mengenai limit fungsi bilangan real. Untuk mengakses materi mengenai Limit Fungsi, silakan kunjungi laman berikut.
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Diberikan fungsi $f:\mathbb{R}\rightarrow\mathbb{R}$ dan $c\in\mathbb{R}$. Tunjukkan bahwa $\lim_{x\rightarrow c}{f(x)}=L$ jika dan hanya jika $\lim_{x\rightarrow 0}{f(x+c)}=L$.
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Jawaban:
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$\Rightarrow$
Akan ditunjukkan $\lim_{x\rightarrow 0}{f(x+c)}=L$. Diambil sebarang bilangan $\epsilon>0$. Karena $\lim_{x\rightarrow c}{f(x)}=L$, maka terdapat $\delta>0$ sehingga untuk setiap $x\in\mathbb{R}$ dengan $0<|x-c|<\delta$ berlaku
\begin{equation*}
|f(x)-L|<\epsilon.
\end{equation*}
Didefinisikan $y=x-c$. Jadi, $x=y+c$. Dengan demikian,
\begin{equation*}
0<|x-c|<\delta \Leftrightarrow 0<|y|<\delta,
\end{equation*}
berlaku $|f(x)-L|<\epsilon \Leftrightarrow |f(y+c)-L|<\epsilon$. Jadi, untuk setiap bilangan $\epsilon>0$, terdapat $\delta>0$ sehingga untuk setiap $y\in \mathbb{R}$ dengan $0<|y-0|<\delta$ berlaku
\begin{equation*}
|f(y+c)-L|<\epsilon.
\end{equation*}
Dengan kata lain,
\begin{equation*}
\lim_{y\rightarrow 0}{f(y+c)}=L \Leftrightarrow \lim_{x\rightarrow 0}{f(x+c)}=L.
\end{equation*}
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$\Leftarrow$
Akan ditunjukkan $\lim_{x\rightarrow c}{f(x)}=L$. Diambil sebarang bilangan $\epsilon>0$. Karena $\lim_{x\rightarrow 0}{f(x+c)}=L$, maka terdapat $\delta>0$ sehingga untuk setiap $x\in\mathbb{R}$ dengan $0<|x|<\delta$ berlaku
\begin{equation*}
|f(x+c)-L|<\epsilon.
\end{equation*}
Didefinisikan $y=x+c$. Jadi, $x=y-c$. Akibatnya,
\begin{equation*}
0<|y-c|<\delta,
\end{equation*}
berlaku $|f(y)-L|<\epsilon. Jadi, untuk setiap bilangan $\epsilon>0$, terdapat $\delta>0$ sehingga untuk setiap $y\in \mathbb{R}$ dengan $0<|y-c|<\delta$ berlaku
\begin{equation*}
|f(y)-L|<\epsilon.
\end{equation*}
Dengan kata lain,
\begin{equation*}
\lim_{y\rightarrow c}{f(y)}=L \Leftrightarrow \lim_{x\rightarrow c}{f(x)}=L.
\end{equation*}
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